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DescriptionQ150
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Q150DVASIC interview problem

Classify an address range

TechniquesRangesEnumBoundary cases
DifficultyEasy
TopicVerification Utilities
LanguageSystemVerilog
Requirements3 checkpoints
01

Problem

Return LOW for [0:16], MED for [17:127], HIGH for [128:256], and OUT otherwise.

Example input and output

Use this case to check your interpretation
Input
unsigned addresses=[0,16,17,127,128,256,257]
Output
classes=[LOW,LOW,MED,MED,HIGH,HIGH,OUT]
Explanation

Both endpoints of each legal interval are inclusive, adjacent class boundaries have no gap or overlap, and 257 is above the highest legal address.

02

Requirements (3)

  • Treat all interval endpoints as inclusive.
  • Represent OUT explicitly.
  • Avoid gaps or overlaps.